x^2+3x+12=2

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Solution for x^2+3x+12=2 equation:


Simplifying
x2 + 3x + 12 = 2

Reorder the terms:
12 + 3x + x2 = 2

Solving
12 + 3x + x2 = 2

Solving for variable 'x'.

Reorder the terms:
12 + -2 + 3x + x2 = 2 + -2

Combine like terms: 12 + -2 = 10
10 + 3x + x2 = 2 + -2

Combine like terms: 2 + -2 = 0
10 + 3x + x2 = 0

Begin completing the square.

Move the constant term to the right:

Add '-10' to each side of the equation.
10 + 3x + -10 + x2 = 0 + -10

Reorder the terms:
10 + -10 + 3x + x2 = 0 + -10

Combine like terms: 10 + -10 = 0
0 + 3x + x2 = 0 + -10
3x + x2 = 0 + -10

Combine like terms: 0 + -10 = -10
3x + x2 = -10

The x term is 3x.  Take half its coefficient (1.5).
Square it (2.25) and add it to both sides.

Add '2.25' to each side of the equation.
3x + 2.25 + x2 = -10 + 2.25

Reorder the terms:
2.25 + 3x + x2 = -10 + 2.25

Combine like terms: -10 + 2.25 = -7.75
2.25 + 3x + x2 = -7.75

Factor a perfect square on the left side:
(x + 1.5)(x + 1.5) = -7.75

Can't calculate square root of the right side.

The solution to this equation could not be determined.

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